A particle is moving along a circular path with a constant speed of 10 ms -1 . What is the magnitude of the change is velocity of the particle, when it moves through an angle of 60° around the center of the circle?
A
Zer
B
10 m/s
C
D
Text Solution
Verified by ExpertsThe correct answer is:
B
= 2vsin 
= 2vsin30° = 2 × 10 × 
= 10 m/s
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